Fraction irréductible : 2/3+ 6/27+ 7/9-5/3. B= (1+1/3)/(3/5) Merci

Question

Mathématiques Publié : 2022-05-04 Mis à jour : 2022-08-17 simghn

Question

Fraction irréductible : 2/3+ 6/27+ 7/9-5/3.

B= (1+1/3)/(3/5)
Merci

Answer 1

Bonjour

Fraction irréductible :

2/3+ 6/27+ 7/9-5/3

= (2 x 3) / (3 x 3) + (3 x 2) / (3 x 9) + 7/9 - (5 x 3) / (3 x 3)

= 6/9 + 2/9 + 7/9 - 15/9

= 15/9 - 15/9

= 0

B= (1+1/3)/(3/5)

B = [(1 x 3) / (1 x 3) + 1/3] x 5/3

B = (3/3 + 1/3) x 5/3

B = 4/3 x 5/3

B = 20/9.