Pouvez-vous m’aider à factoriser 3 svp

E = (4a-3) (4a-3) - (6a+1) (4a-3)

  = (4a-3) [(4a-3) - (6a+1)]

  = (4a-3) (-2a-4)

  = -2 (4a-3) (a+2)

Bonsoir,

Factoriser:

Facteur commun:

• ka - kb = k(a - b)

E = (4a - 3)² - (6a + 1)(4a - 3)

E = (4a - 3)(4a - 3) - (6a + 1)(4a - 3)

E = (4a - 3)(4a - 3 - (6a + 1))

E = (4a - 3)(4a - 3 - 6a - 1)

E = (4a - 3)(-2a - 4)

E = -(4a - 3)(2a + 4)

E = (-4a + 3)(2a + 4)

E = (3 - 4a)(2a + 4)

E = (3 - 4a) * 2(a + 2)

E = 2(3 - 4a)(a + 2) ✅

* = multiplication

Bonne soirée