Mathématiques

Question

Factorisation, bonne chance ...
Factorisation, bonne chance ...

1 Réponse

  • Bonjour,

    G = (2x - 3)^2 - 6x + 9
    G = (2x - 3)(2x - 3 - 3)
    G = (2x - 3)(2x - 6)
    G = 2(2x - 3)(x - 3)

    H = x^30y^55 + x^40y^28
    H = x^30y^28 (y^27 + x^10)

    I = (3x + 3)^2 + (x + 1) - (x + 1)(2x - 3)
    I = (x + 1)(3^2 + 1 - 2x + 3)
    I = (x + 1)(-2x + 13)

    J = (x^2 + 1)^2 + 2(x^2 + 1)(3x + 2) + (3x + 2)^2
    J = a^2 + 2ab + b^2
    J = (a + b)^2
    J = (x^2 + 1 + 3x + 2)^2
    J = (x^2 + 3x + 3)^2

    L = (4 - 2x)(3x + 2) - (3x - 6)(x + 1) + (2 - x)(2x + 2)
    L = 2(2 - x)(3x + 2) - 3(x - 2)(x + 1) + 2(2 - x)(x + 1)
    L = (2 - x)[2(3x + 2) + 3(x + 1) + 2(x + 1)]
    L = (2 - x)(6x + 4 + 3x + 3 + 2x + 2)
    L = (2 - x)(11x + 9)

    M = 4 + (x + 2)(3x - 4) - x^2
    M = 4 - x^2 + (x + 2)(3x - 4)
    M = (2 - x)(2 + x) + (x + 2)(3x - 4)
    M = (x + 2)(2 - x + 3x - 4)
    M = (x + 2)(2x - 2)
    M = 2(x + 2)(x - 1)